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In shown diagram, if voltag...
Question
In shown diagram, if emf of battery is doubled and resistor kept constant then what is the new Power dissipated at resistor ?
A
$4P $
B
$2P $
C
P
D
2P
E
4P
Medium
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Solution
Verified by Toppr
Correct option is
E
4P
Power,
$P=ε_{2}/R$
As R is kept constant so
$P∝ε_{2}$
So,
$PP_{′} =ε_{2}4ε_{2} $
or
$P_{′}=4P$
Thus, option E is correct.
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